Why Do Gluons Decay into u-anti-u Pairs Instead of Z0 Bosons?

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SUMMARY

The discussion centers on the decay of gluons into u-anti-u pairs, emphasizing that this process occurs via the strong force rather than the weak force mediated by Z0 bosons. The Z0 boson, while capable of facilitating such decays, is less favorable due to its off-shell nature, making gluons the preferred choice for these interactions. The participants highlight that in particle physics, gluons are typically utilized for more probable decay processes, while Z0 bosons are reserved for less likely scenarios.

PREREQUISITES
  • Understanding of particle physics concepts, particularly gluons and their role in strong interactions.
  • Familiarity with the weak force and the properties of Z0 bosons.
  • Knowledge of particle decay processes and Feynman diagrams.
  • Basic grasp of on-shell and off-shell particle definitions.
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  • Study the role of gluons in Quantum Chromodynamics (QCD).
  • Research the properties and interactions of Z0 bosons in the Standard Model.
  • Explore Feynman diagrams and their applications in particle decay processes.
  • Investigate the differences between strong and weak forces in particle interactions.
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Students and researchers in particle physics, physicists interested in the interactions of fundamental particles, and anyone seeking to understand the mechanisms behind particle decay processes.

Onjii
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sorry it's a d and anti-d pair!
 
the Z0 boson could do that, but ... weak force is called 'weak' for a reason... the Z0 would be way too off-shell.
It's much more likely that a gluon will do the job... and in most of cases, if you can draw a diagram with a gluon, you'll preferably draw it with that... except for if you are interested to less probable stuff...
 
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Thanks, just the kind of answer i was looking for!
 

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