Why do leaving groups detach from molecules?

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The discussion centers on the nature of leaving groups in chemical reactions, specifically whether their departure is a random event. The mechanism of leaving group loss varies depending on the reaction type. In E1/SN1 mechanisms, the leaving group is involved in an equilibrium process, where the position of the equilibrium is largely random in solution. In contrast, E2/SN2 mechanisms require the presence of the substituting or abstracting group to facilitate the leaving group's departure, indicating a more structured process. Additionally, in reactions like electrophilic aromatic substitution, a base abstracts a proton from an intermediate, further complicating the mechanisms involved. Overall, the randomness of a leaving group's departure is context-dependent, influenced by the specific reaction mechanism at play.
Runei
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Hi,

My question is short and very simple: Is the loss of a leaving group primarily a random event?
What is the actual mechanism that initiates that a specific leaving group.. leaves?

Thanks in advance :)
 
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This depends on the mechanism. If you're familiar with elimination/nucleophilic substitution mechanisms, then the leaving group in the E1/SN1 pathways are either attached or detached from the parent molecule in an equilibrium:
$$R-X\leftrightharpoons R^+ + X^-$$
Which side of the equilibrium a given molecule lies on at any particular moment is largely random in solution. For E2/SN2 mechanisms, the transition state is bimolecular. This means that the substituting/abstracting group needs to be present to effect the loss of the leaving group. For other substitutions, like electrophilic aromatic substitution, a base usually abstracts a proton from the arenium intermediate. More complex mechanisms than this require more complex answers.
 
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Thank you, so much for your answer !
 
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