Why do leaving groups detach from molecules?

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SUMMARY

The discussion centers on the mechanisms of leaving groups detaching from molecules, specifically within the context of elimination and nucleophilic substitution reactions. In E1/SN1 pathways, the detachment occurs in an equilibrium state, where the position of the equilibrium is largely random in solution. Conversely, E2/SN2 mechanisms involve a bimolecular transition state, necessitating the presence of the substituting or abstracting group to facilitate the leaving group's departure. More complex mechanisms may require additional considerations.

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  • Understanding of elimination mechanisms in organic chemistry
  • Familiarity with nucleophilic substitution reactions
  • Knowledge of E1 and SN1 pathways
  • Comprehension of E2 and SN2 mechanisms
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Runei
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Hi,

My question is short and very simple: Is the loss of a leaving group primarily a random event?
What is the actual mechanism that initiates that a specific leaving group.. leaves?

Thanks in advance :)
 
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This depends on the mechanism. If you're familiar with elimination/nucleophilic substitution mechanisms, then the leaving group in the E1/SN1 pathways are either attached or detached from the parent molecule in an equilibrium:
$$R-X\leftrightharpoons R^+ + X^-$$
Which side of the equilibrium a given molecule lies on at any particular moment is largely random in solution. For E2/SN2 mechanisms, the transition state is bimolecular. This means that the substituting/abstracting group needs to be present to effect the loss of the leaving group. For other substitutions, like electrophilic aromatic substitution, a base usually abstracts a proton from the arenium intermediate. More complex mechanisms than this require more complex answers.
 
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Thank you, so much for your answer !
 

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