Why Do Substances in Their Elemental State Have Zero Enthalpy of Formation?

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Discussion Overview

The discussion revolves around the concept of why substances in their elemental state have an enthalpy of formation equal to zero. Participants explore the implications of this definition, its conventions, and the nature of elements in their standard states.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Some participants assert that the zero enthalpy of formation is a convention, suggesting that there must be an agreed-upon reference point for measurements.
  • Others argue that elements simply exist in their standard state and are not formed, implying that this existence justifies the zero enthalpy without the need for a convention.
  • A participant highlights the importance of referring to elements in their standard state, noting that different forms of an element (like graphite vs. diamond) have different enthalpies of formation.
  • There is a discussion about the definition of standard enthalpy of formation, with some participants questioning how to form a substance like O2 from its constituent elements if O2 is already in its most stable form.
  • One participant points out that breaking bonds in O2 requires energy, but forming them again releases energy, leading to a discussion about the implications for enthalpy changes.
  • Another participant emphasizes that the definition of standard enthalpy is a choice of reference point, suggesting that it could be defined differently.

Areas of Agreement / Disagreement

Participants express differing views on whether the zero enthalpy of formation is a convention or a reflection of the nature of elements. There is no consensus on the underlying reasons for this definition, and the discussion remains unresolved.

Contextual Notes

Some participants reference the standard state of elements and the implications of different forms on enthalpy, indicating that the discussion may depend on specific definitions and contexts.

gracy
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substances in their elemental state have enthalpies of formation equal to zero,why?
 
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Convention. There has to be an agreed upon zero, and this is as good as any.
 
Bystander said:
Convention. There has to be an agreed upon zero, and this is as good as any.
so no reason or concept behind this?
 
The "concept" is that measurements have to be made relative to some reference point, or "zero." "How far is Omaha?" "7." "7 what from where?"
 
It is not some sort of convention.
It is just that elements are not formed, they exist like they are. That's it.
You don't form an element, element just exists.

Anyway, it's important to say that you are referring to elements in their standard state. For example, carbon is at standard state in form of graphite. Carbon as diamond has a ΔΗ of formation that's not 0.
 
cseil said:
It is not some sort of convention.

Yes it is.

It is just that elements are not formed, they exist like they are. That's it.
You don't form an element, element just exists.

That doesn't make their standard enthalpy zero. That's just our choice.
 
I am sorry but isn't standard enthalpy of formation defined as the change of enthalpy that comes from the formation of 1 mol of the compound from its elements at the most stable state at 1 atm?

CO2 is formed by C + O2: they are its elementary components, for example. How do you form O2 from its constituent elements if the costituent element at the most stable form is O2?
 
cseil said:
How do you form O2 from its constituent elements if the costituent element at the most stable form is O2?
You take one mole of O2 and turn it into one mole of O2.
 
Bystander said:
You take one mole of O2 and turn it into one mole of O2.

If you break the bonds between the two atoms, of course it takes energy.
But don't you obtain the same energy again when the two bonds are formed again?
 
  • #10
cseil said:
I am sorry but isn't standard enthalpy of formation defined as the change of enthalpy that comes from the formation of 1 mol of the compound from its elements at the most stable state at 1 atm?

As you have stated - it is DEFINED to be that. We could define it differently. Definition selects a reference point.
 
  • #11
cseil said:
But don't you obtain the same energy again when the two bonds are formed again?
Certainly --- and ΔH for such a process is zero. However, what would I accomplish by breaking the bond in the first place? The mole of O2 doesn't need its bonds broken before I use it in whatever process I have in mind --- it's the zero point from which all measurements are made.
 

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