Why Do Two Stones Thrown Off a Cliff Make a Single Splash?

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SUMMARY

The discussion centers on a physics problem involving two stones thrown from a 50m cliff into a calm pool of water. The first stone is thrown downward with an initial velocity of 2m/s, and the second stone is thrown 1 second later. The key calculations involve determining the time it takes for both stones to hit the water, the required initial velocity of the second stone for simultaneous impact, and the final speeds of both stones upon hitting the water. The problem utilizes kinematic equations to derive these values.

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Homework Statement


A person climbs 50m cliff that overhangs calm pool of water. He throws two stones vertically downward, 1s apart, and observes that they cause a single splash. The first stone has an initial speed of 2m/s downward.

(a) How long after release of the first stone do the two stones hit the water?
(b) What initial velocity must the second stone have if they are to hit simultaneously?
(c) What is the speed of each stone at the instant the two hit the water?


Homework Equations


Probably big 6 mechanics. We will have to calculate how long it takes the first stone to hit water then subtract one to get part a.
Once we figure out T we can probably figure out part b.
Not sure about part c.
 
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For part c, once you have the time of flight for each stone, just use the kinematic equation giving the velocity at any time t to find the final speed of each stone.
 

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