Rock thrown off a horizontal cliff

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Homework Help Overview

The problem involves analyzing the motion of two stones: one thrown horizontally from a cliff and the other dropped from the same height. The discussion focuses on comparing their displacement, speed just before impact, and time of fall.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between horizontal and vertical components of velocity, questioning how these affect the speed at impact. There is discussion about the time of fall being the same due to equal initial heights, and the implications of different horizontal velocities on overall speed.

Discussion Status

Participants are actively engaging with the concepts, with some offering analogies to clarify their understanding. There is recognition of the vertical component of velocity being the same for both stones, while the horizontal component differs, leading to questions about the resultant speed at impact.

Contextual Notes

Some participants reference thought experiments involving idealized conditions, such as weightlessness and frictionless surfaces, to frame their reasoning about the motion of the stones.

Kiana Hill
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< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >[/color]

The question states a stone is thrown off a cliff horizontal and it eventually hits the ground. A second stone is dropped from rest at the same height and it hits the ground too. The question asks which are the following quantities are the same or different; displacement, speed right before it hits the ground and time. I know that displacement for the first stone is greater because the resultant is greater. The time, I know, is the same but I believe it is because the initial height is the same so it would take the same amount of time. What I don't get is the speed right before it hits the ground. I am guessing it has to do with the component of velocity, vx and vy but I'm not sure why. All I know for sure is for the first stone, the velocity is the same as the vy and there is no vx, and for the second stone the velocity is at an angle right before it hits the ground but why does that necessarily mean, the velocity is greater?
 
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Exaggerate the situation--imagine a bullet dropped from your hand and another bullet fired horizontally from a gun. Which will have the greater speed (magnitude of resultant velocity vector) upon impact?
 
lewando said:
Exaggerate the situation--imagine a bullet dropped from your hand and another bullet fired horizontally from a gun. Which will have the greater speed (magnitude of resultant velocity vector) upon impact?
That makes way more senses.
 
Kiana Hill said:
why does that necessarily mean, the velocity is greater?
Same reason as for displacement: vy is the same for both but vx is different.
 
I'm assuming that this is one of those weightless strings and frictionless planes type of thought experiment. Therefore my first thought was that the vertical component of velocity will be the same as they will both have been falling for the same time prior to hitting the ground, but one has had extra energy imparted to it in the form of momentum therefore the speed that generates must be in addition to the vertical velocity.
 

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