Why do we never observe the decay of this particle?

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SUMMARY

The discussion centers on the decay processes of the Ʃ(minus) and Ʃ(plus) baryons. The Ʃ(minus) baryon decays into a neutron, an electron, and an electron antineutrino, while the Ʃ(plus) baryon does not decay into a neutron and a positron with an electron neutrino. The distinction arises from their composition; the Ʃ(plus) is made up of two up quarks and one strange quark (suu), necessitating two W boson exchanges, while the Ʃ(minus) consists of two down quarks and one strange quark (sdd), requiring only one W boson exchange. This difference in decay mechanisms is attributed to their roles within an isospin triplet rather than being a particle-antiparticle pair.

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oosgood
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Hey why do we observe the Ʃ(minus) decay into n+e+anti-e-neutrino?But never

Ʃ+--->n + positron+ ve( electron neutrino)
 
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First (although the notation is confusing) [itex]Ʃ^{+}[/itex] and [itex]Ʃ^{-}[/itex] are not a particle-antiparticle pair, they are patners in an isospin triplet. So there is no reason that the two decays should be related. [itex]Ʃ^{+}[/itex] is composed of suu and it would two W exchanges (netral vector bosons don't mix flavour), while [itex]Ʃ^{-}[/itex] is composed of sdd which requires only one W exchange.
 

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