Magnetons
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Why we use Bohr's model of atom in electrostatic?
The discussion centers on the limitations of Bohr's model of the atom in the context of electrostatics. Participants highlight that while Bohr's model is often taught for its simplicity, it fails to account for electromagnetic radiation and the stability of electrons in orbits, leading to inconsistencies. The model is primarily applicable to hydrogen due to its symmetry, but modern quantum mechanics, developed by Born, Jordan, Heisenberg, Schrödinger, and Dirac, provides a more accurate framework for understanding atomic behavior. The consensus is that Bohr's model is outdated and should be reconsidered in educational curricula.
PREREQUISITESPhysics students, educators, and anyone interested in atomic theory and the evolution of quantum mechanics will benefit from this discussion.
Bohr's model also fails in regard to the orbital magnetic moment. However, this is also not relevant in electrostatics.Delta2 said:Because in electrostatics we don't have to worry about electromagnetic radiation, cause that's where Bohr's model fails.
Wekuruman said:Can you explain your question a little bit more and what you have in mind? Can you offer an example where Bohr's model is used in electrostatic?
kuruman said:Can you explain your question a little bit more and what you have in mind? Can you offer an example where Bohr's model is used in electrostatic?
kuruman said:Can you explain your question a little bit more and what you have in mind? Can you offer an example where Bohr's model is used in electrostatic?
Who is "we"? I don't do that. If I talk about shells than I mean orbitals with the same principal quantum number.Magnetons said:I mean we consider k,l,m... Shells where electron is present according to Bohr. Why?
That’s not Bohr’s model, it’s what we get when we solve Schrödinger’s equation for electrons bound electrons.Magnetons said:I mean we consider k,l,m... Shells where electron is present according to Bohr. Why?
How do you see that? Yes, it’s what we get when we solve Schrödinger’s equation. But it is also consistent with Bohr’s model. Do I miss something?Nugatory said:That’s not Bohr’s model