sruthisupriya
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why doesn't 238U decay spontaneously by emitting a proton?
The discussion revolves around the reasons why Uranium-238 (238U) does not spontaneously decay by emitting a proton. Participants explore concepts related to nuclear decay modes, binding energy, and stability of isotopes, with a focus on theoretical and empirical aspects of nuclear physics.
Participants express various viewpoints regarding the mechanisms behind the stability of 238U and the reasons for the absence of proton emission. There is no consensus on a singular explanation, and multiple competing ideas are presented.
The discussion includes references to binding energy calculations and empirical observations related to nuclear stability, but lacks detailed mathematical derivations or specific definitions that may clarify the concepts further.
This discussion may be of interest to those studying nuclear physics, particularly in the areas of nuclear decay processes, isotope stability, and the theoretical frameworks surrounding these topics.
CarlB said:The reaction doesn't happen because it is prevented by energy concerns. In short, a proton and a Pa237 atom weigh more than a U238 atom:
Pa237: 237.0511
H1: 1.0078
Sum: 238.0589
compare to:
U238: 238.0508