Why Does Adding 's' Change to Subtracting 'c' in This Algebraic Expression?

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SUMMARY

The discussion centers on the algebraic manipulation of the expression \frac{a}{b+a+s} + \frac{c*b}{(b+a+s)(c+s)}. Participants confirm that the expression can be rearranged to \frac{a-c}{b+a-c} * \frac{b+a}{b+a+s} + \frac{b}{b+a-c} * \frac{c}{c+s}. A key point is that the term +s does not change to -c, and the correct method to combine the rational expressions involves multiplying by (c+s)/(c+s) to achieve a common denominator.

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roadworx
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Hi,

I have:

\frac{a}{b+a+s} + \frac{c*b}{(b+a+s)(c+s)}

I can rearrange that to:

\frac{a-c}{b+a-c} * \frac{b+a}{b+a+s} + \frac{b}{b+a-c} * \frac{c}{c+s}

Is this correct? If so, can someone tell me why the +s changes into a -c?
 
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You should supply the steps. Also what are you trying to achieve?
A simpler expression is (ac + as + bc)/[(b + a + s)(c + s)].
 
roadworx said:
Hi,

I have:

\frac{a}{b+a+s} + \frac{c*b}{(b+a+s)(c+s)}

I can rearrange that to:

\frac{a-c}{b+a-c} * \frac{b+a}{b+a+s} + \frac{b}{b+a-c} * \frac{c}{c+s}

Is this correct? If so, can someone tell me why the +s changes into a -c?
If your goal is to combine the two rational expressions, multiply the one on the left by 1 in the form of (c + s)/(c + s). That gives you the same denominator in both expressions, so you can then add the numerators.

A +s should not change to a -c.
 

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