Why does Bismuth have a anomalously high Hall value?

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Bismuth exhibits a Hall coefficient that is 1000 times greater than the expected free electron value due to its unique distorted cubic crystal structure, which contains two atoms per unit cell. This significant deviation from the free-electron model arises because Bismuth is a multivalent conductor, making traditional Hall effect formulas inapplicable. Quantum mechanical principles provide a more accurate framework for understanding the Hall effect in Bismuth.

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Bismuth has a hall coefficient 1000 times larger than its free electron value. given that Bi has a distorted cubic structure with 2 atoms per unit cell, suggest a reason for the high hall value.

Any ideas appreciated. Thanks.
 
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For the benefit of the OP and anyone else, Bismuth is not a monovalent element and so the simple formulas for the Hall effect based on the free-electron model and applicable to monovalent conductors are not valid for multi-valent conductors. Quantum mechanics gives approximately correct answers.
 

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