Why does blackbody radiation exist?

In summary, classical and quantum physics predict that every object emits electromagnetic energy in accordance with its temperature, which is useful because it is a purely quantum phenomenon and can't be explained through classical physics.
  • #1
KingNothing
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4
It seems it is predicted by both classical and quantum physics. Why is it predicted in the first place? Is it purely a mathematical reasoning, or is there some qualitative reason why it must exist?

In other words, why would some philosopher/physicist hundreds of years ago say to himself, "I think every object emits electromagnetic energy in accordance with its temperature."?
 
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  • #2
I believe Black body radiation is a purely quantum phenomenon and cannot be explained through classical physics. It is important because of its universal nature. The intensity profile is completely Independent of the source as it comes about because of the distribution of photons in equilibrium.
 
  • #3
KingNothing said:
It seems it is predicted by both classical and quantum physics. Why is it predicted in the first place? Is it purely a mathematical reasoning, or is there some qualitative reason why it must exist?

In other words, why would some philosopher/physicist hundreds of years ago say to himself, "I think every object emits electromagnetic energy in accordance with its temperature."?

One way to see it is through equipartition theorem stating that every degree of freedom (DoF) in thermodynamic equilibrium takes up kT/2 energy on average. If you start with finite number of matter DoF possessing all available energy (i.e. an object at temperature T) coupled to an "array" of infinite number of DoF (i.e. electromagnetic field), final state is that energy would be distributed equal, in a sense; EM field would "suck out" all energy or, if you will, body will radiate out all internal energy. Of course, that would happen either way, but classical physics suggest this energy transfer would be instantaneous - any thermal radiation would have infinite power. Quantum mechanics provides correct explanation of the way matter couples to EM field, more precisely, details how is the interaction suppressed at very high frequencies (Planck hypothesis) thus mitigating unphysical behavior of the system seen by classical approach mentioned above (ultraviolet catastrophe).
 

1. What is blackbody radiation?

Blackbody radiation is the electromagnetic radiation emitted by a perfect blackbody, which is an object that absorbs all wavelengths of light that fall on it. It is also known as thermal radiation because it is produced by the thermal energy of the object.

2. Why does blackbody radiation exist?

Blackbody radiation exists because all objects with a temperature above absolute zero (0 Kelvin or -273.15 degrees Celsius) emit electromagnetic radiation. This radiation is a result of the thermal energy of the object's particles vibrating and moving.

3. How is blackbody radiation related to temperature?

The intensity of blackbody radiation increases with temperature. This is because as the temperature of an object increases, the thermal energy of its particles also increases, causing them to vibrate and move more, and emit more radiation.

4. Why is blackbody radiation important?

Blackbody radiation is important because it is a fundamental concept in physics and plays a significant role in many areas of science, such as astronomy, cosmology, and engineering. It also helps us understand the properties of objects and their temperatures, and has practical applications in technology, such as in the development of thermal imaging devices.

5. How is blackbody radiation measured?

Blackbody radiation can be measured using a spectrophotometer, which detects the intensity of different wavelengths of electromagnetic radiation. The resulting spectrum of the measured radiation can then be compared to the theoretical blackbody spectrum, allowing us to determine the temperature of the object emitting the radiation.

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