How do I calculate modal mass with combined distributed and lumped masses?

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SUMMARY

The discussion focuses on calculating modal mass when combining distributed and lumped masses in structural analysis. The formula for modal mass is defined as M* = ∫m.φ^2(x) dx, where φ(x) represents the mode shape function. The user successfully calculated modal mass for a distributed load of 3000 kg/m over a length of 80m, yielding a result of 54423 kg. The primary challenge addressed was the integration of both distributed and lumped masses in the calculation.

PREREQUISITES
  • Understanding of modal analysis in structural dynamics
  • Familiarity with integration techniques in calculus
  • Knowledge of distributed and lumped mass concepts
  • Proficiency in using mode shape functions, φ(x)
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This discussion is beneficial for structural engineers, students in civil engineering, and professionals involved in dynamic analysis of structures who need to understand the integration of distributed and lumped masses in modal calculations.

thethinwhiteduke
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Homework Statement


The question is featured in the image below. I know the methods to calculate modal mass, stiffness etc, I'm just not too sure how to model both the distributed and lumped masses together.

Q2_zpsjsos7jr0.jpg


Homework Equations


Modal Mass, M* = ∫m.φ^2(x) dx

The Attempt at a Solution


Say for instance, that the tower had no lumped mass at the top, so we only had to consider the distributed load (m = 3000 kg/m), the solution would be:
M* = m∫φ^2(x) dx (limits of integration are from 0 to L(=80m))
∫φ^2(x) dx = ∫(1-cos((πx)/(2L))^2 dx = L - 4L/π + L/2
M* = 3000 x (80 - 320/π +40) = 54423kg

My issue is not knowing how to combine the distributed and lumped masses together for this calculation. Any help is greatly appreciated
 
I've managed to solve the problem now. Thank you for the concern though!
 

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