1. The problem statement, all variables and given/known data Motorcycle in a vertical loop. Traveling at 50 m/s. Assume g=10 m/s^2 Find the maximum height of the loop. h=? 2. Relevant equations F(net) = F(cent) + F(grav) F(cent) = mv^2/r F(grav) = mg (change) KE = (change) PE KE = 1/2 mv^2 PE = mgh 3. The attempt at a solution F(net) solution gives me 500m F(cent) = F(grav) mv^2/r = mg v^2 = gr v^2/g = r r = 250m the height is 500m Conservation of Energy solution gives me 125m KE = PE 1/2mv^2 = mgh (v^2)/(2g) = h 125m = h I found this in an MCAT practice book and they said the correct answer was 500m. Why does the conservation of energy formula not work here?