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tkegis

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## Homework Statement

Motorcycle in a vertical loop.

Traveling at 50 m/s.

Assume g=10 m/s^2

Find the maximum height of the loop. h=?

## Homework Equations

F(net) = F(cent) + F(grav)

F(cent) = mv^2/r

F(grav) = mg

(change) KE = (change) PE

KE = 1/2 mv^2

PE = mgh

## The Attempt at a Solution

F(net) solution gives me 500m

F(cent) = F(grav)

mv^2/r = mg

v^2 = gr

v^2/g = r

r = 250m

the height is 500m

Conservation of Energy solution gives me 125m

KE = PE

1/2mv^2 = mgh

(v^2)/(2g) = h

125m = hI found this in an MCAT practice book and they said the correct answer was 500m.

Why does the conservation of energy formula not work here?

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