Why does Harry's vacation start early?

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The discussion centers on a physics problem involving Harry the painter, who weighs 500 N and uses a rope with a breaking point of 300 N. The rope does not break when tied to his chair due to a static equilibrium condition where the force is distributed across multiple points. However, when Harry ties the rope to a flagpole, the single point of attachment cannot support his weight, resulting in the rope breaking and Harry taking his vacation early. This scenario illustrates the principles of static equilibrium and force distribution.

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Harry the painter swings year after year from his bosun's chair. His weight is 500 N and the rope, unknown to him, has a breaking point of 300 N. Why doesn't the rope break when he is supported as shown to the left below? One day Harry is painting near a flagpole, and, for a change, he ties the free end of the rope to the flagpole instead of to his chair as shown to the right. Why did Harry end up taking his vacation early?


. How does the direction of a friction force compare with the velocity of a sliding object?
 
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parker21 said:
Harry the painter swings year after year from his bosun's chair. His weight is 500 N and the rope, unknown to him, has a breaking point of 300 N. Why doesn't the rope break when he is supported as shown to the left below? One day Harry is painting near a flagpole, and, for a change, he ties the free end of the rope to the flagpole instead of to his chair as shown to the right. Why did Harry end up taking his vacation early?


. How does the direction of a friction force compare with the velocity of a sliding object?
I don't know where your diagram is but I suspect that in the first case the rope is hooked over something and connects to the chair in two places (in which case, each holding so it can support 600 N) and in the second case he just has one piece of rope which breaks when he puts 500 N force on it.

AM
 
AM you are insightful. This is question 34 from chapter 4 of Paul Hewitt's Conceptual Physics text. And your assumption is correct.

Parker21: there is no friction in this problem (at least it is not significant) and you do not compare forces with velocities, and anyway nothing is sliding since this is a "static equilibrium" problem. Read your textbook section 4.7 .
 

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