When a negative charge of -2C is moved from point A to point B, the potential energy of the system increases by 10J, leading to a voltage V(ab) of +5V. The equation used is U=qV, where U represents potential energy, q is charge, and V is voltage. The increase in potential energy indicates that point A is at a higher potential than point B, confirming that the voltage difference is positive. Thus, the correct interpretation of the voltage is V(ab) = +5V.
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Vab is nothing but Va-Vb. In simple words, if you have a positive charge and a negative charge placed close to each other, you'll observe a gain in potential energy of the negative charge if it is moved away from the positive charge. Here, since the negative charge is gaining energy, point A must be at a higher potential (more +ve than B) than point B. Hence, Vab= +5V.Kelly McGuire said:What is the voltage V(ab)?