Why Does Multiplying Pressure by \(10^5\) Help in Calculating Depth?

[iRaid]

Homework Statement

PART B

Homework Equations

$$P = \rho gh$$

The Attempt at a Solution

Well I tried doing 412 = (1025)(9.8)h.. Divide by 10045 (9.8 x 1025). And ended up getting .041..
I found out that I need to use 412 x 10⁵ for the pressure which I have no idea why.

Any help?

Also, the answer is 4100m

 

[berkeman]

Homework Statement

PART B

Homework Equations

$$P = \rho gh$$

The Attempt at a Solution

Well I tried doing 412 = (1025)(9.8)h.. Divide by 10045 (9.8 x 1025). And ended up getting .041..
I found out that I need to use 412 x 10⁵ for the pressure which I have no idea why.

Any help?

Also, the answer is 4100m

You are mixing your units. "Atmospheres" is not an mks unit. You should write units in your equations as you go, to make sure that they are consistent (LSH units = RHS units, and the units of any quantities you are adding are the same).

 

[rock.freak667]

In your equation P=ρgh, P is measured in Pascals (Pa)

 

[iRaid]

Oh right thanks