Why does my diode limiter circuit output ±3.7V and ±4.7V?

[francisg3]

Hello,
I have recently had a lab on diode limiters and am a bit confused by the results. The circuit is seen in the picture below and I have obtained theoretical values for the Voltage output. The circuit is feed by a 16V sine wave with a frequency of 1kHz.

Now I know when the sine wave is positive, D1 conducts and D2 is cut-off. So the voltage output should be 3V + 0.7V = 3.7V right?

When the sine wave is negative I know that D1 is cut-off and D2 conducts. This means that the output voltage should be -4V + 0.7V = -3.3V correct?

I need to sketch the input and output so would the graph would be a sine wave clipped at +3.7V and -4.7V ?

Thanks for the help!

 

[Quinzio]

would the graph would be a sine wave clipped at +3.7V and -4.7V ?

Yes, it would be like this.