Why does pushing a 10 kg object against a wall require 1000 N?

[Sachin Saraogi]

We know that force * coeff. of friction = m * g. . It does not make sense. Pls read details. This is when force is applied perpendicular to the direction of friction. But suppose we say that m = 10 kg, g = 10 m/s2, coeff. of friction is 0.1. Then by formula it says that force required to keep the object against the wall will be 1000 N. How does this make sense? I mean the force required to lift the object without any support is just m*g = 100 N. Pls explain this so that it makes intuitive sense...

 

[Simon Bridge]

We know that force * coeff. of friction = m * g. . It does not make sense.

Of course it doesn't, it is nonsense.

This is not correct ... the usual equation is $F=\mu N$ where "N" is the magnitude of the contact force between the surfaces.
Where that is a horizontal flat surface, $N=mg$ ... which is to say it's the weight of the object.

Pls read details. This is when force is applied perpendicular to the direction of friction. But suppose we say that m = 10 kg, g = 10 m/s2, coeff. of friction is 0.1. Then by formula it says that force required to keep the object against the wall will be 1000 N. How does this make sense?

Oh you mean that you are applying the normal force?

If you want friction to hold a box against it's weight, on a wall that slippery, then sure ... you will need a lot of force... especially if you are only applying the force horizontally.

Please see:
http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html
http://www.engineeringtoolbox.com/friction-coefficients-d_778.html