Calculate Magnitude of Force to Push 10 kg Object 11m, Speed 2 to 5.2 m/s

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SUMMARY

The discussion centers on calculating the magnitude of force required to push a 10 kg object over a distance of 11 meters, increasing its speed from 2 m/s to 5.2 m/s. The initial kinetic energy (Ek) was calculated as 20 J, while the final kinetic energy was determined to be 135 J, leading to a total work done of 115 J. The correct approach involves using the work-energy principle, where the force can be derived from the work done divided by the distance.

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Homework Statement


"A force was used to push a 10 kg object through a distance of 11 metres. Its speed was initially 2 m/s, and was increased to 5.2 m/s at the end of the 11 metres. What was the magnitude of the force?"


Homework Equations


Ek = 1/2 mv^2
W = fd?

The Attempt at a Solution



Initial kinetic energy was 20, final = 143. 123 J of work went into the system. Unsure of what to do from here, or if that was the correct approach. We're reviewing "work and energy" chapter in class, so I would assume it would be along those lines. multiple choice options are 10.5 N, 115 N, 230 N, 23 N.
 
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You know the amount of work that was done and you know the distance the force acted to do that work.
 
Oops. I see my mistake, I was dividing 123 by 11, 143 J at 5.2m/s isn't correct, it's actually 135. Thanks.
 

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