Why Does Reflected Light Experience a Phase Change?

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SUMMARY

Reflected light experiences a 180-degree phase change when reflecting from a medium with a higher index of refraction, while no phase change occurs when reflecting from a medium with a lower index. This phenomenon is quantitatively described by the Fresnel Relations, specifically the equation E' = E_{incident}[(n_1-n_2)/(n_1+n_2)] for normal incidence. The derivation of these relations is covered in standard optics textbooks, such as "Principles of Optics" by M. Born and P. Wolf. The discussion emphasizes the importance of understanding the underlying physics rather than solely relying on textbook references.

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marlon
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Reflected light will experience a 180 degree phase change when it reflects from a medium of higher index of refraction and no phase change when it reflects from a medium of smaller index. This is very well known. However i am wondering why that is ? Can anyone give me some calculations that actually prove this ?

Thanks

marlon
 
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The "Fresnel Relations" in physics-optics give the reflected E' field as
E'=E_{incident}[(n_1-n_2)/(n_1+n_2)] for normal incidence.
This shows the phase change. The FRs are derived in most junior level EM or optics texts. They follow from the BCs on E and H at the interface of two dielectrics.
The transverse components of each are continuous.
 
The theory of reflection of light is presented in any textbook of optics.I liked and recommend the bible:M.Born & P.Wolf:"Principles of Optics",any edition,chapter 1,starting with page 36.


Daniel.
 
Guys, if it is so easy why not give me a specific explanation as to why the phase change happens in this particular case ? Dexter, referring to books is useless because i am never going to read that book. I am asking for an explanation and if you cannot give it then don't post just for the sake of posting...Please...

So my question still stands...Anyone who knows the answer ?


regards
marlon
 
Marlon,the equation Meir posted states that,for normal incidence,

E_{reflected}=E_{incident}\frac{n_{1}-n_{2}}{n_{1}+n_{2}}

If n_{1} < n_{2},then E_{reflected}= - k E_{incident} (1)

,where k=:\frac{n_{2}-n_{1}}{n_{1}+n_{2}}>0 (2)

Okay.Now,u write,following (1) & (2)

E_{reflected}=k E_{incident}e^{i\pi} (3)

Is it any clear?Guess not.I introduce the phases and the polarization vectors,okay,then

\vec{E}_{reflected}=\vec{e_{p}}E_{reflected}e^{i\left(\vec{k}_{reflected}\cdot\vec{r}-\omega t\right)} (4)

Using (3),u see where that phase change comes from.

http://scienceworld.wolfram.com/physics/FresnelEquations.html

(For the graph).

Here's a nice course

http://www.ece.rutgers.edu/~orfanidi/ewa/

BTW,it's PHASE.



Daniel.
 
thanks dexter
 

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