Why Does Sqrt of -1 Appear in Classical Mechanics Wave Equations?

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SUMMARY

The appearance of the square root of -1 in classical mechanics wave equations is crucial for simplifying the manipulation and solution of these equations. Specifically, d'Alembert's solution to the wave equation can be expressed as u(x,t) = F(x-ct) + G(x+ct), which can be reformulated using complex exponentials: f(x,t) = A.exp[i(kx - wt)] and g(x,t) = B.exp[i(kx + wt)]. This approach allows for the encoding of two real solutions through the real and imaginary parts of a complex solution, facilitating easier algebraic manipulation compared to trigonometric functions.

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gaminin gunasekera
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in wave equations sq rt of -1 appears. could you kindly explain why.

cecilgamini
 
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gaminin gunasekera said:
in wave equations sq rt of -1 appears. could you kindly explain why.

cecilgamini
I helps to simplify the manipulation and solution of equations.

d'Alembert's solution to the wave equation would be,

u(x,t) = F(x-ct) + G(x+ct)

which can be re-written as

u(x,t) = f(x,t) + g(x,t)

and we can write

f(x,t) = A.exp[i(kx - wt)]
g(x,t) = B.exp[i(kx + wt)]

where

w = kc.

Although the deformation u(x,t) will clearly have to be a real number for all values of x and t, it turns out to be useful to consider complex soutions to the wave equation as well. The real and imaginary parts of a complex solution will individually satisfy the wave equation, so a complex solution encodes two real solutions.

Where a solution involves trigonometric functions, e.g.

u(x,t) = A.cos(x - ct) + B.cos(x + ct)

rather than a complex exponential function, then the solution and algebraic manipulation of the latter is often much easier than the former.
 

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