Why does the current source trip me up in superposition analysis?

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negatifzeo
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Homework Statement


Three-part circuit diagram for superposition: (a) original circuit with 6 A current source I0, 5 Ω resistor R1, 10 Ω resistor R2 and 45 V source V0, current I through R2; (b) source I0 alone generates I1 with the voltage source removed; (c) source V0 alone generates I2 with the current source removed.

This isn't a homework assignment, this is straight from the textbook. They work it out but I'm still not following, would it be possible for someone to go through this step by step and explain
it clearly? (How to determine the current due to the voltage source and due to the current source.) I can get the right answer when it comes to determining the current due to the voltage source but the current source trips me up. Thanks.


Homework Equations





The Attempt at a Solution


 
For the current source drawing (b): You have 6 A going into the junction. How is the current split between the two resistors? Note that they share the same voltage. Are they in series or in parallel?
For the voltage source (c): You have two resistors that share the same current. How much current do they draw? Are they in series or in parallel?
 
Thanks. My big problem was not realizing I had to convert the current source into a voltage source by placing the parallel resistor in series.