# How does a current source work in Norton's Therom

• dushyanth

#### dushyanth

Hi.i know that a ideal current source has infinite resistance and it supply's constant current to aload connected across it. The current source doesn't have the infinite resistance in series to it but in pparalle. All is well until I think of this Norton's Therom. When we transform a voltage source to current source we connect the same thevinin resistance in parallel to current source (now it's name is Norton's resistance). So for an ideal voltage source the internal residence is zero and all the voltage across it is dropped across the load only. But when we transform it we connect zero resistance across a current source (as per Norton) no current passes through the load as the current source is shorted?? How is it possible that Norton's Therom it's true this case? Correct me if I am wrong.http://www.zen22142.zen.co.uk/Theory/images/norton_th.png

Hi dushyanth. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif [Broken]

Don't overlook the need to set VTh = R × IN

▻ What is the open circuit voltage across AB in each of the above?
▻ What is the short circuit current when you place a short across AB?

http://thumbnails112.imagebam.com/37333/0363e9373324851.jpg [Broken]

Last edited by a moderator:
dushyanth
Hi dushyanth. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif [Broken]

Don't overlook the need to set VTh = R × IN

▻ What is the open circuit voltage across AB in each of the above?
▻ What is the short circuit current when you place a short across AB?

http://thumbnails112.imagebam.com/37333/0363e9373324851.jpg [Broken]

Last edited by a moderator: