Why does the dissolution of NH4NO3 happen if the ∆H is 28.1?

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SUMMARY

The dissolution of ammonium nitrate (NH4NO3) occurs despite a positive enthalpy change (∆H = 28.1 kJ/mol) due to the favorable increase in entropy during the process. The spontaneity of the dissolution can be explained using the Gibbs free energy equation, where the change in free energy (∆G) is negative when the increase in entropy (∆S) outweighs the positive enthalpy change. Additionally, the behavior of phosphoric acid (H3PO4) as an acid after its third dissociation is influenced by the strength of the base involved, with strong bases effectively facilitating this process due to their ability to stabilize the resulting conjugate base.

PREREQUISITES
  • Understanding of Gibbs free energy and its relation to spontaneity
  • Knowledge of enthalpy (∆H) and entropy (∆S) concepts
  • Familiarity with acid-base theories, particularly the Arrhenius concept
  • Basic chemistry of ammonium nitrate and phosphoric acid
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  • Study the Gibbs free energy equation and its applications in chemical reactions
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  • Explore the properties of strong bases and their role in acid-base reactions
  • Investigate the dissociation constants of phosphoric acid and its conjugate bases
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1. Why does the dissolution of NH4NO3 happen if the ∆H is 28.1? I'm supposed to be detailed with an equation, and explaining spontaneity.

Does it happen because of the energy created from protonation?

2. And why is only a strong base able to make H3PO4 act as an acid after the 3rd acid dissociation?

Is it because it is electronically unfavorable?
 
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1) at constant temperature and pressure what concept relates to sponaneity (depends on both entropy and enthalpy of process).

2)In terms of a base, how strong is PO4^2- compared to H2PO4^-1? What is the Arrehnius concept of an acid base neutralization in perspective of the conjugate acid/bases?
 

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