Why Does the Kraus Map Need to be Completely Positive?

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SUMMARY

The discussion centers on the necessity of complete positivity in Kraus maps within Quantum Computation. A positive map, denoted as Φ, transforms a density matrix into another density matrix, but it is the complete positivity that ensures valid outcomes for entangled states in composite systems. Specifically, for separable states represented as ρ = ρ₁ ⊗ ρ₂, the operation (\Phi ⊗ I₂)ρ remains positive, while non-separable states can produce negative eigenvalues under a positive but not completely positive map. Therefore, to guarantee valid density matrices across all scenarios, complete positivity is essential.

PREREQUISITES
  • Understanding of density matrices in Quantum Mechanics
  • Familiarity with Kraus operators and their role in quantum operations
  • Knowledge of separable and non-separable states in quantum systems
  • Basic concepts of positive and completely positive maps
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  • Study the mathematical formulation of Kraus operators in Quantum Mechanics
  • Explore the implications of complete positivity on quantum entanglement
  • Learn about the Choi-Jamiołkowski isomorphism and its relation to positive maps
  • Investigate applications of completely positive maps in quantum information theory
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Quantum physicists, researchers in quantum information science, and students studying quantum mechanics who seek to understand the significance of complete positivity in quantum operations.

Henriamaa
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In Quantum Computation we define a map that takes on density matrix to another. It is represented by some kraus matrices. I do not know why it has to be completely positive.
 
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I'm not active in this area, so take my remarks with a grain of salt.

A positive map \Phi takes a density matrix to another density matrix. The difference between positive and completely positive maps is important for entangled states in combined systems, where the map acts only on one of the systems.

For a seperable state \rho = \rho_1 \otimes \rho_2, a new state (\Phi \otimes I_2)\rho is always positive (I_2 is the identity in the second system). Counterintuitively, non-seperable states can yield negative eigenvalues when acted upon with a positive but not completely positive map.

Since we want our map to yield a valid density matrix in all cases, we require it to be completely positive, that is to say that (\Phi \otimes I_2)\rho has to be positive for arbitrary systems 2 and states \rho.
 

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