Why does the proton have no excited states?

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petergreat
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I've never heard of any excited states of the proton. Why?
By "excited state" I mean something with the same composition (uud) that decays to the proton (plus photons etc.) with nearly 100% branching ratio.
 
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Thanks! One question, though. Does the [itex]\Delta^+[/itex] decay to [itex]p\pi^0[/itex] or to [itex]n\pi^+[/itex] more often? According to Wikipedia on Delta baryons both decay modes exist.
 
In order to answer that question, I'd go to the Particle Data Group and search through the baryon tables, but you might as well do it yourself. :wink:

http://pdg.lbl.gov/
 
I actually check PDG before I posted the previous reply, but I got lost...
I went to Particle Properties -> Baryons, and found a list of reviews. I admit I often don't understand the terminology, but none of them seems to have any information on Delta+ branching ratios.
 
That's because the decays are given by Clebsch-Gordon coefficients and the assumption is anyone can calculate them.
 
Neutrons decay into protons [plus electons and electron antineutrinos].
 
petergreat said:
Thanks! One question, though. Does the [itex]\Delta^+[/itex] decay to [itex]p\pi^0[/itex] or to [itex]n\pi^+[/itex] more often? According to Wikipedia on Delta baryons both decay modes exist.
The ratio of Delta-->pi0 n/Delta-->pi- p is determined by isospin to be 2:1.
 
Thereare a large number of excited states of the proton besides the Delta.
All the states called N* or Delta can be considered excited states of the proton.
They decay mainly into pions and a proton or neutron.
There is a small branching ratio into photon and nucleon.