Why does the proton have no excited states?

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petergreat
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I've never heard of any excited states of the proton. Why?
By "excited state" I mean something with the same composition (uud) that decays to the proton (plus photons etc.) with nearly 100% branching ratio.
 
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Thanks! One question, though. Does the [itex]\Delta^+[/itex] decay to [itex]p\pi^0[/itex] or to [itex]n\pi^+[/itex] more often? According to Wikipedia on Delta baryons both decay modes exist.
 
I actually check PDG before I posted the previous reply, but I got lost...
I went to Particle Properties -> Baryons, and found a list of reviews. I admit I often don't understand the terminology, but none of them seems to have any information on Delta+ branching ratios.
 
petergreat said:
Thanks! One question, though. Does the [itex]\Delta^+[/itex] decay to [itex]p\pi^0[/itex] or to [itex]n\pi^+[/itex] more often? According to Wikipedia on Delta baryons both decay modes exist.
The ratio of Delta-->pi0 n/Delta-->pi- p is determined by isospin to be 2:1.
 
Thereare a large number of excited states of the proton besides the Delta.
All the states called N* or Delta can be considered excited states of the proton.
They decay mainly into pions and a proton or neutron.
There is a small branching ratio into photon and nucleon.