Why does the quantum harmonic oscillator have discrete energy levels?

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SUMMARY

The quantum harmonic oscillator exhibits discrete energy levels due to the action of the ladder operator, denoted as "a". When applying the ladder operator to the ground state wave function \(\psi_0\), the result is zero, confirming that \(\psi_0\) is the lowest energy state. This behavior is fundamental in quantum mechanics, illustrating the quantization of energy levels in harmonic oscillators.

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glederfein
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Hello.
I am trying to use the following equation:
a\left|\psi_n\right\rangle=\sqrt{n}\left|\psi_{n-1}\right\rangle
(where a is the "ladder operator").

What happens when I substitute \psi_n with \psi_0?
 
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oops, sorry for the silly question...
of course I will get 0.
 

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