Why Does the Root Sum Calculation for a Polynomial's Derivative Confuse Many?

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SUMMARY

The discussion centers on the confusion surrounding the root sum calculation for the polynomial's derivative, specifically the polynomial 3x5 - 250x3 + 735x. The first derivative, 15x4 - 750x2 + 735, has roots at -7, -1, 1, and 7, summing to 0, which is incorrect. The correct sum, as per the HMMT solution, is derived from the squares of the roots, yielding 50 for the first derivative and 25 for the second derivative, totaling 75.

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The question is :"The polynomial 3x5-250x3+735x is interesting because it has the maximum possible number of relative extrema and points of inflection at integer lattice points for a quintic polynomial. What is the sum of the x-coordinates of these points?"

I think the answer is 0, but it's wrong.

My solution is :"The first derivative is 15x4-750x2+735, whose roots are -7,-1,1 and 7. The second derivative is 60x3-1500x,whose roots are 0,-5,5. Then, the sum is 0."

The HMMT solution is "The first derivative is 15x4-750x2+735, whose roots sum to 750/15=50. The second derivative is 60x3-1500x,whose roots sum to 1500/60=25, for a grand total of 75."

I really can't understand how it get the sum 50 and 25...Please help me.

Thanks...
 
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The only thing I can say is that they appear to be talking about the sum of x2 where x is a zero of the polynomial:
15x^4-750x^2+735= 15(x^2- 1)(x^2- 49)
so x2= 1 and 49 which add to 50 and
60x3-1500x= 60 x(x^2- 25)
so x2= 0 and 25 which add to 25.
 
HallsofIvy said:
The only thing I can say is that they appear to be talking about the sum of x2 where x is a zero of the polynomial:
15x^4-750x^2+735= 15(x^2- 1)(x^2- 49)
so x2= 1 and 49 which add to 50 and
60x3-1500x= 60 x(x^2- 25)
so x2= 0 and 25 which add to 25.

i think so...
but since we have +7 and -7 and so on...why isn't it 150?
 
thank you all the way...
 

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