Why does the Schwinger parameter correspond to proper length?

  1. I have just learned from nice article


    that the propagator of a massive particle can be rewritten as an integral over the so-called Schwinger parameter t as

    \frac{1}{p^2 + m^2} = \int\limits_0^\infty dt \exp(-t(p^2 + m^2))

    In addition, in the blog article it is said that this Schwinger parameter p can be interpreted as the proper length of the propagator. I dont see this, so can somebody give a derivation/further explanation?
  2. jcsd
  3. fzero

    fzero 3,003
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    1 person likes this.
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