Why Does the Second Harmonic Frequency Double in a Fixed Rope?

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Homework Statement



If the fundamental frequency for a rope fixed at both ends is 30Hz, what is the frequency of the second harmonic?


Homework Equations



v=f*wavelength



The Attempt at a Solution



correct answer is 60Hz. Can somebody please explain? Thank you.
 
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In the fundamental mode of vibration, the rope contains one loop which is λ/2. In the second harmonic the number of loops are two. Then what is the new wavelength?