Why does using the substitution u=x^2 help evaluate the limit as x approaches 0?

  • Thread starter Thread starter JustinLiang
  • Start date Start date
  • Tags Tags
    Limit
Click For Summary

Homework Help Overview

The discussion revolves around evaluating a limit as x approaches 0, specifically involving the substitution u = x^2. Participants are trying to understand the implications of this substitution in the context of a limit problem presented in a math exam.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore different interpretations of the limit expression and question the grammatical clarity of the original problem. There are attempts to apply known limits and factor expressions, but confusion arises regarding the correct formulation and the outcome of the limit.

Discussion Status

Some participants have suggested that using the substitution u = x^2 is beneficial for simplifying the limit expression. There is acknowledgment of the complexity of the limit, and while some guidance has been offered, there is no explicit consensus on the correct approach or interpretation of the problem.

Contextual Notes

Participants note the potential ambiguity in the problem statement and express uncertainty about how to derive the limit value of 4/5 from the given expressions. There is also mention of using L'Hôpital's rule, but the effectiveness of this method is still under discussion.

JustinLiang
Messages
79
Reaction score
0

Homework Statement


http://www.prep101.com/files/Math100PracticeExam.pdf

Question 1m

The Attempt at a Solution


I tried to do this by using
lim sinx/x = 1
x->0

Factoring out x^2 from each one and I get infinity.
Why does this method not work?

The answer says it's 4/5.

I even tried plugging in 0.001 in my calculator and I get infinity :S.
 
Last edited by a moderator:
Physics news on Phys.org
Is that sin(2x^2), sin^2(2x), sin(2)x^2 ?
 
QuarkCharmer said:
Is that sin(2x^2), sin^2(2x), sin(2)x^2 ?

Or is it 3sin(2x^2-6x^2+4x^6)? The question isn't very grammatical. And however I rearrange it I still can't figure out how to pull 4/5 as a limit out.
 
Dick said:
Or is it 3sin(2x^2-6x^2+4x^6)? The question isn't very grammatical. And however I rearrange it I still can't figure out how to pull 4/5 as a limit out.

It is 3sin(2x^2), you get 4/5, this limit is INSANE :P
 
It helps to use the substitution u=x2 to get
[tex]\lim_{u \to 0}\frac{3 \sin 2u - 6u + 4u^3}{u^5}[/tex]Then three applications of the Hospital rule gets you to a limit you can evaluate.
 
vela said:
It helps to use the substitution u=x2 to get
[tex]\lim_{u \to 0}\frac{3 \sin 2u - 6u + 4u^3}{u^5}[/tex]Then three applications of the Hospital rule gets you to a limit you can evaluate.

Ah, indeed it does.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K