Why doesn't Rubidium decay to Strontium?

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Discussion Overview

The discussion centers around the beta decay of Rubidium-87 (##^{87}_{37}Rb##) to Strontium-87 (##^{87}_{38}Sr##), exploring the stability of Rubidium and the implications of its long half-life compared to other isotopes like Uranium-235 and Vanadium-50. The scope includes theoretical considerations of nuclear stability and decay rates.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant calculates the most stable atomic number (Z) for a given mass number (A) and finds that for A=87, Z=38 is the most stable, questioning why Rubidium does not beta decay to Strontium.
  • Another participant asserts that Rubidium does beta decay with a half-life of approximately 4.8 x 1010 years, referencing external sources.
  • A participant questions the stability of Rubidium given its long half-life, prompting further inquiry into what the expected half-life should be.
  • Another participant compares Rubidium's half-life to that of Uranium-235, suggesting that Rubidium should decay quicker if it is more stable to undergo beta decay.
  • One participant mentions Vanadium-50's significantly longer half-life, contributing to the discussion about the variability of half-lives among different isotopes.

Areas of Agreement / Disagreement

Participants express differing views on the implications of Rubidium's half-life and its stability, with no consensus reached regarding the expected decay rates or the reasons behind the observed stability.

Contextual Notes

Participants do not clarify the assumptions behind their calculations or the definitions of stability and decay rates, leaving some aspects of the discussion unresolved.

unscientific
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Both ##^{87}_{37}Rb## and ##^{87}_{38}Sr## are odd-even nuclei, so we can ignore the pairing term ##\delta##. I tried to calculate the most stable Z for a given A by finding ##\frac{\partial B}{\partial Z} = 0##. That gives the most Z-stable value of ##Z_0 = \frac{2\gamma A}{4\gamma + \epsilon A^{\frac{2}{3}}}## which is ##38## for ##A=87##.
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If that's the case, then why wouldn't Rb beta decay to Strontium as these are naturally occurring isobars.
 
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unscientific said:
why wouldn't Rb beta decay to Strontium

87Rb does, in fact, beta-decay with a half-life of about 4.8 x 1010 years. See e.g. http://www.nndc.bnl.gov/chart/
 
jtbell said:
87Rb does, in fact, beta-decay with a half-life of about 4.8 x 1010 years. See e.g. http://www.nndc.bnl.gov/chart/

Then why is it so stable with such a long half-life?
 
unscientific said:
Then why is it so stable with such a long half-life?

What do you think it's half life should be?
 
Vanadium 50 said:
What do you think it's half life should be?

My question is since it is more stable to undergo beta decay, why doesn't it undergo decay quicker? For example uranium 235's half life is 10 times shorter.
 
unscientific said:
For example uranium 235's half life is 10 times shorter.

And Vanadium-50's is a million times longer. What do you think it's half life should be?
 
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Vanadium 50 said:
And Vanadium-50's is a million times longer. What do you think it's half life should be?
I get your point.
 

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