Why Doesn't the Intermediate Value Theorem Apply to ln(x^2 + 2) on [−2, 2]?

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Discussion Overview

The discussion revolves around the application of the Intermediate Value Theorem (IVT) to the function f(x) = ln(x^2 + 2) on the interval [−2, 2]. Participants explore whether the IVT can provide information about the existence of zeros of the function within this interval, particularly given that the function evaluates to the same positive value at both endpoints.

Discussion Character

  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • Some participants argue that since f(-2) and f(2) both yield the same positive value (ln(6)), the IVT does not apply, suggesting no zeros exist in the interval.
  • Others reference the textbook explanation, which states that the IVT does not guarantee a zero exists if both endpoint values are positive, indicating a lack of contradiction with the theorem.
  • A participant questions the relevance of the values being the same, suggesting that the positivity of the values is the critical factor for the IVT's applicability.
  • Another participant emphasizes that the IVT only asserts the existence of a zero if one endpoint is negative and the other is positive, leaving open the possibility of zeros existing even when both values are positive or negative.

Areas of Agreement / Disagreement

Participants express differing views on the implications of the IVT in this context. There is no consensus on whether the IVT can provide any information about zeros in the given interval, as some maintain it does not apply while others argue that it does not rule out the existence of zeros.

Contextual Notes

Participants highlight that the application of the IVT depends on the signs of the function values at the endpoints, and the discussion reveals uncertainty regarding the implications of having both values positive.

nycmathdad
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Explain why the Intermediate Value Theorem gives no information about the zeros of the function
f(x) = ln(x^2 + 2) on the interval [−2, 2].

Let me see.

Let x = -2.

f(-2) = ln((-2)^2 + 2)

f(-2) = ln(4 + 2)

f(-2) = ln (6). This is a positive value.

When I let x be 2, I get the same answer.

So, f(-2) = f(2).

So, I conclude by saying that the Intermediate Value Theorem does not apply here because both answers are the same value and both are positive.

However, the textbook answer is different.

Textbook Answer:

"This does not contradict the IVT. f (−2) and f (2) are both positive, so there is no guarantee that the function has a zero in the interval (−2, 2)."
 
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nycmathdad said:
Explain why the Intermediate Value Theorem gives no information about the zeros of the function
f(x) = ln(x^2 + 2) on the interval [−2, 2].

Let me see.

Let x = -2.

f(-2) = ln((-2)^2 + 2)

f(-2) = ln(4 + 2)

f(-2) = ln (6). This is a positive value.

When I let x be 2, I get the same answer.

So, f(-2) = f(2).

So, I conclude by saying that the Intermediate Value Theorem does not apply here because both answers are the same value and both are positive.

However, the textbook answer is different.

Textbook Answer:

"This does not contradict the IVT. f (−2) and f (2) are both positive, so there is no guarantee that the function has a zero in the interval (−2, 2)."
I see no problem whatsoever.
20210322_145040.jpg
 
nycmathdad said:
Explain why the Intermediate Value Theorem gives no information about the zeros of the function
f(x) = ln(x^2 + 2) on the interval [−2, 2].

Let me see.

Let x = -2.

f(-2) = ln((-2)^2 + 2)

f(-2) = ln(4 + 2)

f(-2) = ln (6). This is a positive value.

When I let x be 2, I get the same answer.

So, f(-2) = f(2).

So, I conclude by saying that the Intermediate Value Theorem does not apply here because both answers are the same value and both are positive.

However, the textbook answer is different.

Textbook Answer:

"This does not contradict the IVT. f (−2) and f (2) are both positive, so there is no guarantee that the function has a zero in the interval (−2, 2)."
On the contrary the textbook answer is giving the part of YOUR answer that is important! you said "both are positive". The other part of what you said "both answers are the same value" is not important. What if both answers had been 0?
 
Country Boy said:
On the contrary the textbook answer is giving the part of YOUR answer that is important! you said "both are positive". The other part of what you said "both answers are the same value" is not important. What if both answers had been 0?

I'm curious, what if both answers are 0? I say the Intermediate Value Theorem does not apply.
 
I don't know what you mean by "both answers are 0". The answer to the question is NOT a number, it is an explanation, a sentence. And both you and the textbook say that the explanation is that "both f(2) and f(-2) are positive"- 0 is not between them.

An important point is that this does NOT tell us that there is no zero between -2 and 2. The intermediate value theorem says that IF f(a) is negative and f(b) is positive then there is a zero between a and b. It says nothing at all about what happens if f(a) and f(b) are both positive or both negative. There might be a zero between a and b or there might not.
 
Country Boy said:
I don't know what you mean by "both answers are 0". The answer to the question is NOT a number, it is an explanation, a sentence. And both you and the textbook say that the explanation is that "both f(2) and f(-2) are positive"- 0 is not between them.

An important point is that this does NOT tell us that there is no zero between -2 and 2. The intermediate value theorem says that IF f(a) is negative and f(b) is positive then there is a zero between a and b. It says nothing at all about what happens if f(a) and f(b) are both positive or both negative. There might be a zero between a and b or there might not.

Here is what you said:
"On the contrary the textbook answer is giving the part of YOUR answer that is important! you said "both are positive". The other part of what you said "both answers are the same value" is not important. What if both answers had been 0?"
Read your question at the end.
 

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