Why don't these methods give me the same answer?

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SUMMARY

The discussion centers on the calculation of time taken for a proton to traverse the 27.00 km tunnel of the Large Hadron Collider (LHC) at a speed of 0.999997828 times the speed of light. Two approaches were employed to determine the time from the proton's reference frame, yielding different results. The first approach, using Lorentz transformations incorrectly, produced a time of 9.30 x 10-8 seconds, while the second approach correctly calculated the time as 1.88 x 10-7 seconds. The discrepancy arises from the misapplication of event definitions in the first approach.

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Homework Statement


The tunnel of the Large Hadron Collider is 27.00 km long. The LHC accelerates protons to a speed of 0.999997828 times the speed of light. How long would it take the proton to pass through the tunnel according to an observer at rest with respect to the building? To an observer moving with the proton?

∆x=27.00 km = 9.00 x 10-5light seconds
v=0.999997848c

Homework Equations


Δx′=γ(Δx−vΔt)
Δt′=γ(Δt−vΔx/c2)
L=L0
ΔT=γΔT0

The Attempt at a Solution


For an observer at rest with respect to the building
vav=Δx/Δt
∆t=9.00 x 10-5 seconds

I think that part is fine. I tried two different approaches to finding the time in the reference frame of the proton, and got two different answers.

First approach
Treat this as two events:
Event 1) at t=0 and x=0 the proton is at one end of the collider. Then
t' = 0 s and
x' = 0 light seconds
event 2) at t= 9.00 x 10-5 seconds and x= 9.00 x 10-5 light seconds the proton is at the other end of the collider. Using the Lorentz transformations with v= 0.999997824 c, I get
x'= 9.39 x 10-8 light seconds
t'=9.39 x 10-8 seconds

So ∆t = 9.30 x 10-8 seconds - 0 seconds = 9.30 x 10-8 seconds.

Second Approach
From the perspective of the proton, the collider moves towards it at 0.999997824 c. The collider has a rest length of 9.00 x 10-5 light seconds, so an observer moving with the proton sees L, where
L=L0/γ = 9.00 x 10-5 light seconds * 0.00208614
=1.88 x 10-7 light seconds.

A body of that length moves past the observer in time t:
t =L/v= 1.88 x 10-7 light seconds/0.999997824 c =1.88 x 10-7 seconds.

The second approach is getting me twice the time of the first approach. I also see the same discrepancy in the relativistic lengths. I know I am overlooking something fundamental, but cannot see what.
 
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Any help would be appreciated. A:The first approach is incorrect. The two events have to be:Event 1: x = 0, t' = 0Event 2: x' = 9.00 x 10-8 light seconds, t = 9.00 x 10-5 secondsThe second approach is correct. The time dilation factor is the same for both events.
 

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