Why is -2/2 Added in the Manipulation of the Numerator in Laplace Transform?

[juice34]

I need help with a inverse laplace L^-1{[(s/2)+(5/3)]/[s^2+4s+6]} My book says we have to manuipulate the numerator and it says [(s/2)+(5/3)]=(s+2)/2 +5/3-2/2. I have no idea where the -2/2 came from can someone help me out? I will be greatly appreciated.

Jay G.

 

[Mute]

s/2 = (s+2)/2 - 2/2

 

[juice34]

Thanks

Thanks guys, i figured it out.