Why is -2/2 Added in the Manipulation of the Numerator in Laplace Transform?

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    Laplace Properties
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SUMMARY

The discussion centers on the manipulation of the numerator in the inverse Laplace transform L^-1{[(s/2)+(5/3)]/[s^2+4s+6]}. The key transformation involves rewriting (s/2) as (s+2)/2 - 2/2, which simplifies the expression for easier computation. This technique is essential for correctly applying the inverse Laplace transform to the given function. The clarification provided by Jay G. confirms the necessity of this manipulation in the process.

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juice34
I need help with a inverse laplace L^-1{[(s/2)+(5/3)]/[s^2+4s+6]} My book says we have to manuipulate the numerator and it says [(s/2)+(5/3)]=(s+2)/2 +5/3-2/2. I have no idea where the -2/2 came from can someone help me out? I will be greatly appreciated.

Jay G.
 
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s/2 = (s+2)/2 - 2/2
 
Thanks

Thanks guys, i figured it out.
 

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