Why is a branched line in R2 not a topological manifold?

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Discussion Overview

The discussion revolves around the question of why a branched line in R2 does not qualify as a topological manifold. Participants explore the definitions and properties of topological manifolds, particularly focusing on the existence of charts at points of branching.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant asks for an explanation regarding the lack of a chart at the branching point of a branched line in R2.
  • Another participant suggests constructing a chart using a subset of the branch containing the point of branching, proposing a mapping that appears to be continuous and invertible.
  • A participant challenges this by stating that the proposed mapping does not originate from an open subset of R2.
  • Further clarification is provided that an open set in the standard topology must be a union of open balls, which the proposed subset does not satisfy.
  • Participants discuss the concept of "connectedness" and suggest that understanding related concepts, such as "cut points," may help in proving the original claim.

Areas of Agreement / Disagreement

Participants express uncertainty and seek clarification on the definitions and properties involved. There is no consensus reached regarding the construction of a chart or the implications of connectedness in this context.

Contextual Notes

Limitations include the participants' varying levels of understanding of topological concepts and the definitions of open sets within the standard topology on R2.

Who May Find This Useful

This discussion may be useful for individuals studying topology, particularly those interested in the properties of manifolds and the implications of branching in geometric contexts.

CSteiner
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Is there a topologist out there that wants to explain why exactly a branched line in R2 is not not a topological manifold? I know it's because there doesn't exist a chart at the point of branching, but I don't understand why not. I'm just starting to self study this, so go easy on me :).
 
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CSteiner said:
but I don't understand why not.
How do you suggest such a chart is constructed?
 
Well why don't we form a chart (U, x) where U is an element of the subset topology of the standard topology on R2. Then U can be a subset of of the branch containing the point of branching with open endpoints on each of the three branches. x can then map each of these points to a point in R2. This mapping seems to be invertable, and continuous in both directions.
 
But it is not a mapping from an open subset of R^2.
 
Orodruin said:
But it is not a mapping from an open subset of R^2.
Why not? Sorry if this seems like a stupid question, but I'm only just now learning (and trying to understand) the definitions of these things. Open means that it belongs the standard topology on R2, right? Why doesn't it?
 
Because it is not a union of balls. This is the very definition of the standard topology.
 
CSteiner said:
Is there a topologist out there that wants to explain why exactly a branched line in R2 is not not a topological manifold? I know it's because there doesn't exist a chart at the point of branching, but I don't understand why not. I'm just starting to self study this, so go easy on me :).

Do you know the concept of "connected"?
 
micromass said:
Do you know the concept of "connected"?
Not rigorously.
 
You should learn about that then. Learn about "cut points" too. With that you can prove your OP.
 
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micromass said:
You should learn about that then. Learn about "cut points" too. With that you can prove your OP.
Will do, thanks for pointing me in the right direction.
 

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