That's because in the unbroken Standard Model, everything must be massless except perhaps the Higgs particle. This is because left-handed and right-handed parts have gauge-multiplet mismatches, and the Higgs particle is necessary for bridging this gap.
The Standard Model's charged elementary fermions have mass terms that look like this:
(mass) . (left-handed part of EF field) . (right-handed part of EF field)+ + Hermitian conjugate (+ = HC)
In the unbroken SM, the EF fields break down into these gauge multiplets:
Left-handed quark, I = 1/2, Y = 1/6
Right-handed up quark, I = 0, Y = 2/3
Right-handed down quark, I = 0, Y = -1/3
Left-handed lepton, I = 1/2, Y = -1/2
Right-handed neutrino (if it exists), I = 0, Y = 0
Right-handed electron, I = 0, Y = -1
I = weak isospin, Y = weak hypercharge
Hermitian conjugate, same I, - Y
I'm ignoring generations here for simplicity. The muon and the tau are essentially additional flavors of electron, etc.
Electric charge Q = I3 + Y
I3 = -I to I in integer steps, like angular momentum
That makes bare Dirac masses impossible in the Standard Model, or at least so it seems. A left-handed part and a right-handed part, when combined, have I = 1/2 and Y = +- 1. That means that there must be some additional field with I = 1/2 and Y = 1 or -1 to cancel that out and make a proper interaction term. That field is the Higgs particle, with I = 1/2, Y = 1.
We get Higgs-coupling terms
(Higgs) . (coupling) . (left-handed quark) . (right-handed up quark)+
(Higgs)+ . (coupling) . (left-handed quark) . (right-handed down quark)+
(Higgs) . (coupling) . (left-handed lepton) . (right-handed neutrino)+
(Higgs)+ . (coupling) . (left-handed lepton) . (right-handed electron)+
Their (I,Y) sets:
(1/2,1/2) . (1/2,1/6) . (0,-2/3)
(1/2,-1/2) . (1/2,1/6) . (0,1/3)
(1/2,1/2) . (1/2,-1/2) . (0,0)
(1/2,-1/2) . (1/2,-1/2) . (0,1)
If the Higgs particle has a nonzero vacuum field value, then that field value can combine with the coupling to make a Dirac mass.