Why Is My Calculation of EMF in Electromagnetic Induction Incorrect?

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SUMMARY

The calculation of the induced electromotive force (emf) in a straight wire moving through a magnetic field was discussed, specifically using a magnetic flux density (B) of 0.5T and a wire length of 5cm. The correct formula for emf is given by emf = vBLsin(θ), where θ is the angle between the velocity vector and the magnetic field. The discrepancy arises from the angle used; the angle should be 30 degrees, not 60 degrees, leading to the correct induced emf of 0.0125 V as per the book's answer.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for induced emf: emf = vBLsin(θ)
  • Knowledge of magnetic flux density (B) and its units
  • Basic trigonometry to calculate angles in electromagnetic contexts
NEXT STEPS
  • Study the derivation of Faraday's Law of Electromagnetic Induction
  • Learn about the effects of angle on induced emf in different configurations
  • Explore practical applications of electromagnetic induction in generators
  • Investigate the role of magnetic field strength in induced emf calculations
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in understanding the principles of electromagnetic induction and its applications in real-world scenarios.

uzair_ha91
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Electromagnetic Induction Problem : Help needed
The flux density B in a region between the pole faces of a horse shoe magnet is 0.5T directed vertically downward. Find the emf induced in a straight wire 5cm long, perpendicular to B when it is moved in a direction at an angle of 60 degrees with the horizontal with a speed of 100 cm/s...

Answer in book= 0.0125 V

I'm getting 0.022 V by applying the formula: emf=vBLsin60
It's supposed to be quite straightforward, what am i missing then?
 
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the angle 60 is measured to the horizontal, so the magnetic field is at angle of 30 degrees to the wire.
 

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