Why is parity maximally violated in weak interactions?

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Parity is considered maximally violated in weak interactions primarily due to the behavior of W bosons, which couple exclusively to left-handed fermions. In contrast, Z bosons couple to both left and right-handed particles, indicating that parity is not maximally violated in their interactions. The breaking of electroweak symmetry leads to the emergence of massive W bosons and a Z boson that interacts differently based on particle charge. The term "maximally violated" originated from early observations of charged current weak interactions, which displayed equal contributions from vector and axial vector components. This distinction highlights the unique nature of weak interactions compared to other fundamental forces.
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Why do they always say parity is maximally violated in weak interaction? This is true for W boson interactions. But not for Z bosons, as the Zs couple to both left and right handed particles. And hence, is not maximally violated in the case of Z.
 
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Electroweak symmetry is broken; this is one symptom. The unbroken symmetry contains a w1, w2 and w3 that couple to left-handed fermions and a B0 that couples to both handednesses. When the symmetry breaks, the w1 and w2 become the massive W+ and W-, but the w3 and B0 mix to produce a photon which couples to both, and a Z0 which couples purely left-handedly to neutral particles, and progressively more right-handedly to particles with more charge.
 
touqra said:
Why do they always say parity is maximally violated in weak interaction? This is true for W boson interactions. But not for Z bosons, as the Zs couple to both left and right handed particles. And hence, is not maximally violated in the case of Z.
The term "maxilmally violated" arose 50 years ago because the charged current weak interactions, which were the only ones seen for a long time, had equal parts of V and A.
 

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