Why is potential energy considered negative in an inversed pendulum system?

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SUMMARY

The discussion centers on the concept of potential energy in an inverted pendulum system, specifically addressing why potential energy (PE) is considered negative. The potential energy is defined as PE = mgz, where z is negative due to the chosen coordinate system that places the origin (O) at the top. The confusion arises from the textbook's treatment of height (h) and the reference point for zero potential energy, which is not clearly defined in the discussion.

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  • Understanding of gravitational potential energy (PE = mgz)
  • Familiarity with coordinate systems in physics
  • Basic knowledge of pendulum mechanics
  • Concept of reference points in energy calculations
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Andrax
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we have an inversed pendulum(ignore the car)
cart.gif

and we choose the coordinate system to be upwards
the potential energy PE=mgz (z will be hegative since( O,k) is upwards right?) z is always under O.
but in the textbook they basically take the absolute value of h i don't understand why?
 
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Where is the textbook putting the zero of h?
 
ModusPwnd said:
Where is the textbook putting the zero of h?

at the point of rest of the pendulum (same as O)
 
fixed the problem (h ad to do with angle being negatgive which means the work of p is negative)
sorry my explication of the question was off , close this thread
 

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