Why Is the Electric Flux from a Point Charge Only Half Through the XY Plane?

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SUMMARY

The total electric flux through the x-y plane from a point charge +Q located 1 meter below the plane is exactly Q/2. This conclusion arises from Gauss's Law, which states that the electric flux through a closed surface is proportional to the enclosed charge. Since the point charge is symmetrically positioned, only half of the electric field lines intersect the x-y plane, resulting in the flux being halved.

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  • Understanding of Gauss's Law
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  • Knowledge of point charge behavior in electrostatics
  • Basic concepts of symmetry in physics
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  • Explore electric field line visualization techniques
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Hammed
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A point charge +Q is located 1 m below the x-y plane. What is the total electric flux passing through the x-y plane? I know the answer should be Q/2 but how?
 
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Imagine field lines emanating radially from that point charge. Which field lines will cross that plane? Which will never make it to that plane?
 
Hammed said:
A point charge +Q is located 1 m below the x-y plane. What is the total electric flux passing through the x-y plane? I know the answer should be Q/2 but how?
How will the flux lines be arranged around the charge? What symmetry is there?
 

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