Why is the Factorial of Zero Defined as One?

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ananthu017
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can u give me the method to find the factorial of zero ?
 
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[itex]0!=\Gamma(1)=\intop_{0}^{\infty} t^{1-1}\exp(-t)\mathrm{d}t=-[\exp(-t)]_{0}^{\infty}=-(0-1)=1.[/itex]

Alternatively, there's exactly one way to arrange an empty set.
 
DeIdeal said:
[itex]0!=\Gamma(1)=\intop_{0}^{\infty} t^{1-1}\exp(-t)\mathrm{d}t=-[\exp(-t)]_{0}^{\infty}=-(0-1)=1.[/itex]

I highly doubt the OP would be able to make heads or tails of this.

[tex]n! = n(n-1)![/tex]

Work with this definition, it's all you need.
 
So your answer to the original question is that [itex]0!= 0(-1)![/itex]? But what is (-1)!?

(Yes, you can write that 1!= 1(0!) and, if you know that 1!= 1, then it follows that 0!= 1. But better is just to state the basic definition of n! that asserts 0!= 1 for as part of the definition.)