Why Is the Work Done by Weight Zero When Pushing a Box Horizontally?

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Homework Help Overview

The problem involves calculating the work done on a box by its weight and by an applied force while pushing it horizontally. The box has a weight of 100N and is pushed a distance of 2m with a force of 40N.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between work, force, and displacement as vectors. Some question why the work done by weight is considered zero in this context, while others explore the implications of the directions of these vectors.

Discussion Status

Participants are actively engaging with the concepts of work and vector directions. Some have provided insights into the reasoning behind the zero work done by weight, while others are clarifying the relationship between the forces and the displacement involved.

Contextual Notes

There is an emphasis on understanding the vector nature of work, force, and displacement, and how their orientations affect the calculation of work done. The discussion includes considerations of different scenarios, such as pushing the box on an incline.

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Homework Statement


A box of weight 100N is pushed a distance or displacement of 2m with a force of 40N. What is the work done on the box by i) the weight and ii) by the 40N force?

Homework Equations


Work = force * distance

The Attempt at a Solution


i) The work done on the box by weight = 0 (if this is correct, why?)

ii) The work done on the box by the 40N force
Work = force * distance
Work = 40 * 2
Work = 80N
 
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Work, force, and displacement are vectors. Can you figure out "why" from there?
 
I'll just say ths, work done by weight is 0 because that fat box did not helping you out AT ALL

Now, if it was on an incline sliding down as you pushed it..
 
Jack21222 said:
Work, force, and displacement are vectors. Can you figure out "why" from there?

Let me see... weight is acting vertically downwards, while force and displacement are acting horizontally. Therefore the weight had no influence on the force and displacement?

cronxeh said:
I'll just say ths, work done by weight is 0 because that fat box did not helping you out AT ALL

Now, if it was on an incline sliding down as you pushed it..

Thanks very much, you made it clearer
 

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