- #1

David Donald

- 31

- 0

## Homework Statement

A box of m= 25 kg is pulled by a rope with a force of tension, F = 40 N inclined at an angle of 30o with the horizontal, there is no friction between the box and the ground.

b) Determine

the acceleration of the box.

c) Write the equation to find the acceleration

of the box in presence of a friction force of 3.0

N.

d) If a small box of 5kg with a frictional force of 2.0 N is placed against the right side of the box. Would the big box move? If so what would its acceleration be?

Please check my work and let me know if I've made any mistakes..

## Homework Equations

## The Attempt at a Solution

B) F = ma

(40N*Cos(30))/(25kg) = acceleration = 1.38 m/s^2

C)

∑Fx = F - Ff = ma

= (40N(cos(30) - 3N)/(25kg) = 1.26 m/s^2

d) So for this one I used the same equation I came up with in C) except mass is now 30kg because it's 25 kg box + the 5 kg box and the friction force is now 5 N

∑Fx = F - Ff = ma

= (40N(cos(30) - 5N)/(30kg) = 0.988 m/s^2

Now I don't know how to answer the word part... I would say yes it would move because their is a positive acceleration