Why is Water Essential for Life?

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Discussion Overview

The discussion revolves around a mathematical expression that appears to contain a typo, with participants attempting to clarify and correct the notation related to a double integral involving trigonometric and exponential functions.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant questions the meaning of "ye" in the context of a mathematical expression.
  • Another participant suggests that "ye" was likely a typo and proposes a corrected version of the integral.
  • A different participant humorously acknowledges the typo, contributing to the light-hearted tone of the discussion.
  • Further clarification is provided by another participant, who confirms the correction and elaborates on the intended mathematical expression, including its evaluation.
  • Participants express appreciation for the humor in the discussion, indicating a collaborative atmosphere.

Areas of Agreement / Disagreement

There is a general agreement on the existence of a typo and the proposed correction, but the discussion remains focused on clarifying the mathematical expression rather than reaching a definitive conclusion.

Contextual Notes

The discussion does not resolve the initial ambiguity regarding the notation, as it relies on assumptions about the intended mathematical expression.

aldrinkleys
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What does ye" mean?

From here:
wtdPV.png
 
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I rather suspect that was a typo. I suspect that it was something like
[tex]\int_Q\int (x sin y- y e^x)dx dy[/tex]
instead.
 




Sorry, couldn't help it :biggrin:
 
Last edited by a moderator:


Thanks Borek, we need more humour.
 


HallsofIvy said:
I rather suspect that was a typo. I suspect that it was something like
[tex]\int_Q\int (x sin y- y e^x)dx dy[/tex]
instead.

but, look:

5EZ6U.png


From Calculus II, Apostol, p 360
 


Yes, and that makes it obvious, does it not, that what was intended was
[tex]\int_{-1}^1 (x sin(y)- ye^x)dx= \left[\frac{1}{2}x^2sin(y)- ye^x\right]_{-1}^1[/tex]
[tex]= -ye^{1}+ ye^{-1}= -ey+ \frac{y}{e}[/tex]
 


Thanks.
 

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