Joppy MHB Messages 282 Reaction score 22 May 22, 2017 #2 RTCNTC said: Why is x^2 + 1 irreducible? What do you think? If you factor this expression, what do you get? Moreover, what could be said about those factors in relation to the real numbers?
RTCNTC said: Why is x^2 + 1 irreducible? What do you think? If you factor this expression, what do you get? Moreover, what could be said about those factors in relation to the real numbers?
Joppy MHB Messages 282 Reaction score 22 May 22, 2017 #4 Indeed! In this case we could say that the expression is irreducible over the reals, but reducible over the complex numbers. But I might let someone else chime into give a more formal approach. :)
Indeed! In this case we could say that the expression is irreducible over the reals, but reducible over the complex numbers. But I might let someone else chime into give a more formal approach. :)
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 May 23, 2017 #7 RTCNTC said: What about x^2 + x + 1? What does the discriminant tell you about the roots of this quadratic polynomial?
RTCNTC said: What about x^2 + x + 1? What does the discriminant tell you about the roots of this quadratic polynomial?
mathdad Messages 1,280 Reaction score 0 May 23, 2017 #8 b^2 - 4ac 1^2 - 4(1)(1) 1 - 4 -3 b^2 - 4ac < 0 This means no real solutions.