Why L' Hospital's rule cannot apply directly for sequence

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Discussion Overview

The discussion revolves around the application of L'Hospital's rule to sequences, particularly addressing the conditions under which it can or cannot be applied. Participants explore the nature of sequences as discrete functions and the implications for continuity and differentiability.

Discussion Character

  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants assert that L'Hospital's rule cannot be applied directly to sequences because the function defined on natural numbers is discontinuous and thus not differentiable.
  • One participant explains that the graph of a sequence consists of discrete points, which implies discontinuity, and that a function that is not continuous is also not differentiable.
  • Another participant suggests that L'Hospital's rule can be applied if the sequence can be represented as a continuous function by allowing n to take real values instead of just integers.
  • There is mention of specific cases, such as the limit of a rational function, where L'Hospital's rule is applicable, contrasting it with sequences like factorials that are difficult to extend to real variables.

Areas of Agreement / Disagreement

Participants express differing views on the applicability of L'Hospital's rule to sequences, with no consensus reached on the conditions under which it can be applied.

Contextual Notes

Limitations include the dependence on the definitions of continuity and differentiability, as well as the challenges in extending certain sequences to continuous functions.

Kenji Liew
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Homework Statement



Well, this thread is purposely to clarify my question on the use of L'Hospital's rule for sequence.
As I have read from the calculus book, the sequence can be defined such that f:N → ℝ with function f(n)= an where n inside natural numbers,N.

So, we cannot apply L' Hospital rule directly is because the function above is discontinuous on natural numbers and then not differentiable?

Homework Equations



When we plot the graph f(n) versus n, we don't have a continuous graph. Is this mean discontinuous?


The Attempt at a Solution

 
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Kenji Liew said:

Homework Statement



Well, this thread is purposely to clarify my question on the use of L'Hospital's rule for sequence.
As I have read from the calculus book, the sequence can be defined such that f:N → ℝ with function f(n)= an where n inside natural numbers,N.

So, we cannot apply L' Hospital rule directly is because the function above is discontinuous on natural numbers and then not differentiable?

Homework Equations



When we plot the graph f(n) versus n, we don't have a continuous graph. Is this mean discontinuous?


The Attempt at a Solution


The graph of a sequence represents a discrete (separated) set of points. The graph is discontinuous, which is a synonym for not continuous. A function that isn't continuous is also not differentiable. However, you can often extend the sequence to a function that is continuous and differentiable.
 
Thanks for your prompt reply. I think I can understand after looking at your explanation.
 
If you have, for example, \lim_{n\to\infty}\frac{3n^2+ 3n-1}{5n^2- 5n+ 2}, then you can use L'hopital's rule. \lim_{x\to\infty} f(x)= a if and only if \lim_{n\to\infty} f(x_n)= a for every sequence x_n such that x_n that goes to infinity.

So if you have a sequence that can be written as a continuous function (by allowing n to have any real number as a value rather than only integer values) then you can use L'Hopital's rule. On the other hand, things that cannot be extended to all real numbers, such as "n!", cannot be (easily) extended to real variables, cannot be done that way.

(n! can be extended to the "gamma function" but trying to apply L'Hopital's rule to that is likely to be exteremely difficult.)
 

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