Why my answer is wrong? - remove electron from orbital

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Discussion Overview

The discussion revolves around the question of which orbital electrons are removed from when forming Ni+ and Ni2+ ions from a neutral nickel atom. Participants explore the electron configuration of nickel and the energy levels of the 4s and 3d orbitals, debating the order of electron removal.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant questions why electrons are removed from the 4s orbital instead of the 3d orbital, given that the 3d orbital is considered to have higher energy.
  • Another participant explains that 4s electrons are further from the nucleus and require less energy to remove, despite being in a higher energy level.
  • There is mention of differing electron configurations in textbooks, with one participant noting that their textbook shows electrons being removed from the 3d orbital first.
  • A participant discusses the concept of "late fillers" regarding d orbitals and how this relates to the filling order of electrons in the periodic table.

Areas of Agreement / Disagreement

Participants express confusion and differing interpretations regarding the removal of electrons from the 4s versus the 3d orbital, indicating that there is no consensus on the reasoning behind the order of electron removal.

Contextual Notes

Participants reference the electron configuration of nickel and the periodic table, highlighting potential discrepancies in educational materials and the complexity of energy levels in orbitals.

zhen
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why my answer is wrong? --- remove electron from orbital

question:
In forming Ni+ and Ni2+, the nickel atom loses electrons from which orbital(s)?

I looked at the periodic tale, and Ni is in the middle, where the 3d orbital located. so when you need to remove one or two electrons, you should remove from the 3d orbital. but that is not right?

the answer for that is 4s instead of 3d orbital. i don't get it. the 3d should have higher energy than 4s, so how can you remove the 4s, but not 3d first?
 
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G"day, Zhen.

As the names indicate, 4s electrons are one energy level higher than the 3d electrons. The 4s electrons are furthest from the nucleus (and have lower energy levels shielding) so require the least amount of energy to remove.
 
Unco said:
G"day, Zhen.
As the names indicate, 4s electrons are one energy level higher than the 3d electrons. The 4s electrons are furthest from the nucleus (and have lower energy levels shielding) so require the least amount of energy to remove.

But the electron configuration of Ni is [Ar] 4s2, 3d8, shouldn't you remove the electron from the 3d8 first? Even though youn sounds right, I still have a little confusion.
 
zhen said:
But the electron configuration of Ni is [Ar] 4s2, 3d8, shouldn't you remove the electron from the 3d8 first? Even though youn sounds right, I still have a little confusion.
We write it [Ar] 3d8 4s2
(albeit with superscripts)

The d orbitals are "late fillers". By "fill" I refer to the number of electrons increasing as you go across the periodic table.

Look at your periodic table:
Ca doesn't have any 3d electrons but has two 4s electrons. It's not until you get to Sc that an electron fills the 3d subshell.

So in that sense, the 4s electrons fill before the 3d electrons. But the 3d subshell is part of the n=3 energy level, and is "below" the 4s subshell.

This most certainly will be discussed in your textbook.

~ ~ ~ ~ ~ ~ ~

General question (I'm new): is there a way to prevent formatting (ie. line breaks) from disappearing upon previewing?
 
thanks very much, i am really appriciated.
 

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