Undergrad Why quantum wave function collapse is not consider a signal?

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The discussion centers on the implications of quantum wave function collapse and the non-communication theorem in the context of the double slit experiment with entangled particles. Participants explore whether one observer's measurement can influence another's results, particularly when one observer uses a sensor and the other does not. The conversation raises questions about the nature of interference patterns and the conditions under which they can be observed, especially when considering time dilation effects on entangled particles. Clarifications are requested regarding the coherence of the arguments presented, emphasizing the need for clear communication in discussing complex quantum concepts. Ultimately, the dialogue highlights the intricate relationship between measurement, entanglement, and interference in quantum mechanics.
danielhaish
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I read about the non-communication theorem and I understand why when changing one practical will not change the other . But suppose that there is two observers that doing the double slit experiment, but using it with two entanglement practicals. observer one should send signal of yes or no ,he would know which signal to send only in six on clock ,and the other observer knows that he should get yes no(0,1) answer at six on clock . the observer who should send the message may measure the first practical location for sending "yes" and not measure it for sending "no". and then in six on clock the other observer may check weather the electron/photon interference with it self. so basically data was send even though the observers send data before six on clock slower then the light.
of curse for checking the interference we need a lot of entanglement practicals ,so my main question is what happen if two people will do the double slit experiment, and one of them will put sensor in one of the slit and the other will not . would it block the interference in both experiences ?
by shooting the entanglement practicals one by one ,one in one observer side and the other and in secend observer side .
I also have another question what happen to two entanglement practicals in two time zones. in one of them the time going fast and in the other slow . if one of them would stop existing does the it wave function stay collapsed
 
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danielhaish said:
then in six on clock the other observer may check weather the practical interfere with it self . if it does it means the message is no and if it doesn't the answer is yes
No. There is nothing he can measure locally that will tell him if the other particle has been measured.
 
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Dale said:
No. There is nothing he can measure locally that will tell him if the other particle has been measured.
but how can one practical Interference if the possibility to go from bot side is Constance then it wouldn't go from both side
 
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You are talking about interferences. Are you sure that Bob and Alice see interferences if the pair is maximally entangled?
 
danielhaish said:
but how can one practical Interference if the possibility to go from bot side is Constance then it wouldn't go from both side
This is unintelligible. Please write more carefully. Use proper English to the absolute best of your ability, and more importantly be clear about exactly what measurement you are trying to describe.
 
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Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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