Why Start Theories with SO(n,1) and Compactify to SO(3,1)xG?

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SUMMARY

The discussion centers on the common practice of starting theoretical models with a spacetime symmetry represented by SO(n,1) (where n>4) and subsequently compactifying to SO(3,1)xG, where G is an arbitrary symmetry group. The rationale behind this approach is to ensure Lorentz symmetry across the entire space, allowing for a broader range of symmetries by utilizing larger rotation groups. The conversation highlights the importance of Dynkin diagrams in identifying groups that contain SO(3,1) as a subgroup, emphasizing that multiple groups can fulfill this criterion.

PREREQUISITES
  • Understanding of SO(n,1) and its role in spacetime symmetries
  • Familiarity with compactification techniques in theoretical physics
  • Knowledge of Dynkin diagrams and their application in group theory
  • Basic concepts of Lorentz symmetry and its implications in physics
NEXT STEPS
  • Research the properties and applications of SO(n,1) in theoretical physics
  • Study compactification methods and their significance in string theory
  • Explore the use of Dynkin diagrams for classifying Lie algebras
  • Investigate alternative symmetry groups that contain SO(3,1) as a subgroup
USEFUL FOR

The discussion is beneficial for theoretical physicists, graduate students in physics, and researchers exploring higher-dimensional theories and symmetry groups in the context of modern physics.

timb00
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Hi how,

in my master project I am working on extra dimensions and I am asking my self
why is it common to start most of the theories with a space time symmetry given by
SO(n,1) (n>4) and then compactify the obtained spectrum to SO(3,1)xG (where G is an abitrary symmetry group).

Because I think there might be other groups which have the SO(3,1) as subgroup as well?

In my question I said that "most of the theories" working in such a way. This means that all models I have seen, working in that fashion.

I hope you understand my question, otherwise ask and i will do my best to explain my
question further.

best regards,

timb00

P.s. : sorry for my bad English.
 
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Because then you start out with having Lorentz symmetry in the whole space. What kind of spacetime symmetries in the whole space would you propose? :)
 
Because there is a finite amount of groups and the bigger they get the more symmetries they contain. They usually look at SO(p,q) bigger than S0(3,1) in spatial dimensions because the conformal group doesn't have enough symmetry hence moving to a bigger rotation group will allow for more symmetry and then you can compactify the extra spatial dimensions to get around that. Also going back to what I said about a finite amount of groups you can look at dynkin diagrams to show you this hence finding a group that contains S0(3,1) is not unique.
 

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